WebMar 17, 2024 · When you have a belt that is 1/2 iron ore and 1/2 coal, a burner inserter will feed itself some of the coal, as well as supplying ore and coal to the furnace. BUT a burner inserter put on the other side of the furnace to place iron plates on the belt will NOT feed itself coal, despite that there is coal in the furnace. It should work, but it doesn't. I'm … WebAccumulators are not the only way to work with solar energy. Sometimes it is more economical to just avoid consuming energy at night. For example, if you power a bunch of electric mining drills and electric furnaces to produce iron and copper plates , you could build more drills and furnaces than you actually need, and store the excess metal ...
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WebFor example: If an Assembling machine 3 (210kW) and an Electric mining drill (90kW) are on a network (90+210 = 300kW), but the network only has 3 Solar panels (3×60kW = 180kW) to power them, the Assembling machine and Mining drill will both run at 60% speed (180/300=0.6). Drain – The energy consumed by the machine whether it is active … WebNov 20, 2024 · A stock electric mining drill can harvest 0.5 items a second (or 1 item every 2 seconds, or 30 items a minute). A stone furnace can smelt a single iron ore in 3.2 seconds, thus 18.75 iron ore a minute. But, "0.7" … host smbus controller
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WebThe distance from the centre of the mining drill to search for resources in. This is 2.49 for electric mining drills (a 5x5 area) and 0.99 for burner mining drills (a 2x2 area). The drill searches resource outside its natural boundary box, which is 0.01 (the middle of the entity); making it 2.5 and 1.0 gives it another block radius. Web2.) Electric mining drills produce 1 ore every 2 seconds: 90 drills required for a fully saturated belt. 3.) -10% for the relatively early obtainable mining productivity bonus: 81 Drills. 4.) 3x Speed Module 3 for a speed bonus of 150%: 81*0.33 (?) = 26.73, or 27 Mining drills for a fully saturated blue belt. WebSolar panels and accumulators Optimal ratio. The optimal ratio is 0.84 (21:25) accumulators per solar panel, and 23.8 solar panels per megawatt required by your factory (this ratio accounts for solar panels needed to charge the accumulators).This means that you need 1.428 MW of production (of solar panels) and 100MJ of storage to provide 1 MW of … psychology behaviourism exam questions